Then multiply this by the molar mass of NaClO which has a label of g/mol so all labels cancel. Finally multiply by 100 to get a percent!) 6. The label on the commercial bleach reports the percent by mass NaClO to be 6.0%. Calculate the percent error of your value, assuming that the
kg HCl = 6.0 × 105 ton HCl soln 100 ton HCl soln 1 ton 2.205 lb 30 ton HCl 2000 lb 453.6 g 1 kg ? kg HCl = 6.0 × 105 ton soln 3 100 ton soln 1 ton 1 lb 10 g = 1.6 108 kg HCl 88. A typical nonobese male has about 11 kg of fat. Each gram of fat can provide the body with about 38 kJ of energy. If this person requires 8.0 103 kJ of energy per day to survive, how many days could he survive on his fat alone?
A CASE STUDY Activity-based Costing and Pricing Submitted by: Maryland Tano August 24, 2011 Requirements: 1. Using direct labor-hours as the base for assigning manufacturing overhead cost to products, do the following: a. Determine the predetermined overhead rate that will be used during the year. Data given: * Estimated manufacturing overhead cost $ 2,200,000 * Direct labor hours 50,000 hours Answer: Predetermined overhead rate = $ 2,200,000 = $ 44 per DLHs 50,000 hrs b. Determine the unit product cost of one pound of the Kenya Dark coffee and one pound of the Viet Select coffee.
I need to analyze the types of carbohydrates that I am consuming and make sure that the majority are whole grains and nutrient dense. Protein 14.6% of kCal’s from my intake came from protein and according to the AMDR’s range of 10-35%, my protein intake is on the low side. I have to consume more protein to decrease my disease risk. Some examples of food that I should add to my diet are legumes, fish and skinless poultry. With the help of the Intake Compared to DRI report I was able to identify the nutrients in which I was deficient in during my three day analysis.
If the mean weight for men his age is 175 with a standard deviation of 14 pounds and the mean weight for women is 145 with a standard deviation of 10 pounds, determine whose weight is closer to "average." Write your answer in terms of z-scores and areas under the normal
Multiplication and division were performed here as part of the equation. According to the results, people who may be at the height of 65 inches and weigh between 146.2lbs and 174.2lbs may be overweight. 25.1(4096)/703<W<29.9(4096)/703 102809.6/703<W<122470.4/703 146.2<W<174.2 INEQUALITIES 4 For this last weight interval, we shall find those who may be obese at this height. For this compound inequality, all I need to do is take the middle and right terms of the basic inequality and substitute 30 for 29.9. I multiplied the terms and then divided them.
Early research suggests that 1000 mg daily of stevioside, a chemical compound in stevia, might reduce blood sugar levels after meals by 18% in people with type 2 diabetes. Stevia and Obesity: Eating too many calories is often the cause of obesity. Added sugars are roughly 16 percent of all calories people consume. Sodas, fruit drinks and energy drinks contain high amounts of these sugars. Liquids don't satisfy as much as solid foods, so people tend to lose track and compensate for the calories in their drink with the calories they eat.
I have also upped my fruit intake to at least two servings a day which is an increase from the .5 or 1 serving a day I was consuming when I did the assignment on week one. It is very important to get your daily intake of vitamins and minerals, which you can get a substantial amount from fruits and vegetables. One aspect of my diet and nutrition that I feel I do a good job on is proper supplementation. To get your daily recommended intake of vitamins and minerals you would need to eat about five to six thousand calories a day. Of course, if you ate five to six thousand calories a day you would gain a substantial amount of weight very quickly.
Then finally I divide all 3 by 703 in order to isolate W. 128.8 < W < 166.7 So people with the height of 73 inches could have a longer than average life span if they weigh between 129 and 167 pounds. The next equation 23<703WH^2<25 I first multiply all 3 terms by H^2 in order to take our the denominator. 23H^2 < 703W < 25H^2 Then I divide all terms by 703 to isolate the W. 23H^2703<W< 25H^2703 After doing this it now becomes an equivalent inequality for me to solve the second weight. I now use my height squared to find the second weight interval. 23(5329)703<W< 25(5329)703 After I multiply I end up with 122567703<W< 133225703 Then I simply divide and end up with 174 < W < 189.5.
Concentrating on the input of the health care professional, the family and also the challenges and obstacles that they may encounter. There has to be a holistic approach in the promotion of health and wellbeing and consistent support available when needed to maintain it. According to the NHS guidelines to maintain an ideal weight the daily calorie intake for the average male is 2500cal and 2000cal for women, depending on factors like age and physical activity. Healthy BMI ranges from 18.5 to 24.9, below 18.5 is underweight and above 25 is overweight (NICE Guidelines, 2006 ) The Department of Health (2011) states that in the UK alone 63% of the male population is overweight or obese; 23.1% of children from 4-5 years of age and 33.3% of 10 – 11 year olds are overweight or obese. The UK has one of the biggest problems with obesity compared to the rest of Europe and cardiovascular disease is the main cause of death in the UK (British Heart Foundation, 2008).